Mass of $0.5 \mathrm{~kg}$ is attached to a string moving in horizontal circle with angular velocity 10…

Mass of $0.5 \mathrm{~kg}$ is attached to a string moving in horizontal circle with angular velocity 10 cycle/min. Keeping the radius constant, tension in the string is made 4 times by increasing angular velocity '\omega'. The value ' $\omega$ ' of that mass will be
  1. $\frac{1}{3}$ cycle $/ \mathrm{s}$
  2. $\frac{1}{2}$ cycle $/ \mathrm{s}$
  3. $\frac{1}{5}$ cycle $/ \mathrm{s}$
  4. $\frac{1}{4}$ cycle $/ \mathrm{s}$

Solution

The angular velocity needs to be doubled to make the tension 4 times. So, if the initial angular velocity is 10 cycles/min, the new angular velocity will be: $\omega^{\prime}=2 \times 10=20 \text { cycles } / \mathrm{min}$ Answer: (1) 20 cycles/min.

Asked in: MHT CET 2020 (12 Oct Shift 2)

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