Marks obtains by all the students of class 12 are presented in a freqency distribution with classes of equal…

Marks obtains by all the students of class 12 are presented in a freqency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12. If the number of students whose marks are less than 12 is 18, then the total number of students is
  1. $52$
  2. $48$
  3. $44$
  4. $40$

Solution

$\begin{aligned} & \text {Median }=\ell+\left(\frac{\frac{\mathrm{N}}{2}-\mathrm{F}}{\mathrm{f}}\right) \times \mathrm{h} \\ & =12+\left(\frac{\frac{\mathrm{N}}{2}-18}{12}\right) \times 6=14 \\ & \Rightarrow\left(\frac{\frac{\mathrm{~N}}{2}-18}{12}\right) \times 6=2 \\ & \frac{\mathrm{~N}}{2}-18=4 \Rightarrow \mathrm{~N}=44\end{aligned}$ ~

Asked in: JEE Main 2025 (23 Jan Shift 1)

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