Magnetic flux through a coil of resistance $10 \Omega$ is changed by $\Delta \phi$ in $0.1 \mathrm{~s}$. The…

Magnetic flux through a coil of resistance $10 \Omega$ is changed by $\Delta \phi$ in $0.1 \mathrm{~s}$. The resulting current in the coil varies with time as shown in the figure. Then $|\Delta \phi|$ is equal to (in weber)
  1. 6
  2. 4
  3. 2
  4. 8

Solution

$ \text { As } \begin{aligned} e=\frac{\Delta \phi}{\Delta t} & \text { or } R i=\frac{\Delta \phi}{\Delta t} \quad(\because e=R i) \\ \Rightarrow \quad \Delta \phi & =R(i . \Delta t) \\ & =R \times \text { area under } i-t \text { graph } \\ = & 10 \times \frac{1}{2} \times 4 \times 0.1=2 \text { weber } \end{aligned} $

Asked in: JEE Main 2012 (12 May Online)

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