M grams of steam at 100 o C is mixed with 200 g of ice at its melting point in a thermally insulated…

M grams of steam at 100oC is mixed with 200g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40oC [heat of vaporization of water is 540cal/g and heat of fusion of ice is 80cal/g ], the value of M is ________

Solution

MiceLf+Mice40-0Cw=MsteamLv+Msteam100-40Cw
20080+401=M540+601
200120=M600
M=40 gm

Asked in: JEE Main 2020 (07 Jan Shift 2)

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