Local maximum and local minimum values respectively of the function $f(x)=(x-1)(x+2)^2$ are

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Aicharya · Accepted Answer

$\begin{aligned} & f(x)=(x-1)(x+2)^2 \ & f^{\prime}(x)=(x+2)^2+(x-1) 2(x+2)=(x+2)(x+2+2 x-2)=3 x(x+2) \ & \stackrel{+}{+}-0_{-2}^{+} \ & f_{\max }=f(-2)=0 \ & f_{\min }=f(0)=-4\end{aligned}$

Local maximum and local minimum values respectively of the function $f(x)=(x-1)(x+2)^2$ are

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