Lithium forms BCC structure having edge length of unit cell $351 \mathrm{pm}$ then atomic radius of lithium is

Lithium forms BCC structure having edge length of unit cell $351 \mathrm{pm}$ then atomic radius of lithium is
  1. 75 pm
  2. 152 pm
  3. 180 pm
  4. 210 pm

Solution

$\sqrt{3} a=4 r$ $r=\frac{\sqrt{3} \times 351}{4}=151.98 \mathrm{pm}$

Asked in: MHT CET 2022 (08 Aug Shift 1)

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