Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700…

Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 mmHg, respectively, at the same temperature. Then correct statements is:
( xM=Mole fraction of 'M' in solution;
xN=Mole fraction of 'N'in solution;
yM=Mole fraction of 'M' in vapour phase;
yN=Mole fraction of 'N' in vapour phase; )
  1. xMxN>yMyN
  2. xMxN=yMyN
  3. xMxN<yMyN
  4. xM-yM<xN-yN

Solution

PMo  is given as=450 mm of Hg.

PNo  is given as=700 mm of Hg.

We know that PM=xM×P MO Raoult’s law.

PN=xN×P NO Raoult’s law.

From Dalton’s law PM=yM×PT

PN=yM×PT

So,

xM×P Mo=yM×PT  (i)

xM×PNo=yN×PT    (ii)

(i) (ii) xMxN×P  MoP  No = yMyN

xMxN=yMyN×750450

xMxN>yMyN

Asked in: JEE Main 2019 (09 Apr Shift 1)

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