Lines $3x + 4y = 12$ and $6x + 8y = 24$ are

Lines $3x + 4y = 12$ and $6x + 8y = 24$ are
  1. coincident
  2. parallel
  3. intersecting
  4. perpendicular

Solution

$\dfrac{3}{6} = \dfrac{4}{8} = \dfrac{12}{24} = \dfrac{1}{2}$.

Asked in: MH-SSC-9

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