lim z → 1   z ( 1 / 3 ) − 1 z ( 1 / 6 ) − 1 =

limz→1 z(1/3)−1z(1/6)−1=
  1. -1
  2. 1
  3. 2
  4. -2

Solution

limz→1 z(1/3)−1z(1/6)−1

We know that limx→a xm−amxn−an=mnam-n

limz→1 z13−113z16−116

Here m = 13, n = 16 & a=1

=13161

=2.

Asked in: AP EAMCET 2021 (19 Aug Shift 1)

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