lim x → 1 ( 1 - x ) 1 - x 2 ⋯ ⋯ 1 - x 2 n ( 1 - x ) 1 - x 2 ⋯ ⋯ 1 - x n 2 =…

limx1(1-x)1-x21-x2n(1-x)1-x21-xn2=¯,nN
  1. Pn2n
  2. Cn2n
  3. (2 n) !
  4. (2n)!n!

Solution

limx1(1-x)1-x21-x2n(1-x)1-x21-xn2  nN

limx1(1-x)1-x21-x2n1-x2n(1-x)1-x21-xn21-x2n

limx11-x1-x×1-x21-x.............×1-x2n1-x1-x1-x×1-x21-x×.................×1-xn1-x2

Apply L'hospital rule

limx1-1-1×-2x-1×...........×-2n×x2n-1-1-1-1×-2x-1×................-nxn-1-12

limx11×2×3×..........×2n1×2×3×............n2

=2n!n!2=Cn2n

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

Practice more Limits questions on Aicharya