lim x → 0 48 x 4 ∫ 0 x t 3 t 6 + 1 d t is equal to

limx048x40xt3t6+1dt  is equal to 

Solution

Let

L=limx0480xt31+t6dtx400

Applying L'hospital rule, we get

L=limx048x31+x64x3

L=limx0121+x6

L=12

Asked in: JEE Main 2023 (30 Jan Shift 1)

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