Mathematics › Definite Integration › Leibnitz Rule of Differentiation
Let
L=limx→048∫0xt31+t6dtx4→00
Applying L'hospital rule, we get
L=limx→048x31+x64x3
⇒L=limx→0121+x6
⇒L=12
Asked in: JEE Main 2023 (30 Jan Shift 1)
Practice more Definite Integration questions on Aicharya