lim n → ∞ n ( 2 n + 1 ) 2 ( n + 2 ) n 2 + 3 n - 1

limn→∞n(2n+1)2(n+2)n2+3n-1
  1. 0
  2. 2
  3. 4
  4. ∞

Solution

Given limit, limn→∞n(2n+1)2(n+2)n2+3n-1

=limn→∞n·n22+1n2n1+2nn21+3n-1n2

 =(2+0)2(1+0)(1+0+0) ∵n→∞, 1n→0.

=4

Asked in: AP EAMCET 2021 (20 Aug Shift 1)

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