lim n → ∞ 1 + 2 + … + n n 3 2 =

limn1+2++nn32=
  1. 0
  2. 23
  3. 1
  4. 32

Solution

The expression is given as,

I=limn1+2+.+nn32

=limn1+2+..+nnn

=limn1n1n+2n++nn

=r=1nlimn1n1n

=01xdx

=23x3201=23

Asked in: AP EAMCET 2019 (21 Apr Shift 2)

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