lim n → ∞ 1 1 + n + 1 2 + n + 1 3 + n + … + 1 2 n is equal to :-

limn11+n+12+n+13+n++12n  is equal to :-

  1. 0
  2. loge2
  3. loge32
  4. loge23

Solution

We have,

limn11+n+12+n+13+n++12n

=limn11+n+21+n+31+n+.+1n+n

=limn r=1n1n+r

=limn r=1n1n11+rn

=0111+xdx

=loge1+x01

=loge2

Asked in: JEE Main 2023 (01 Feb Shift 1)

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