Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is

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Aicharya · Accepted Answer

Ratio of amplitudes, $\frac{a_1}{a_2}=\frac{3}{2}$ $	herefore \quad \begin{aligned} a_1 & =3 k, a_2=2 k \ \frac{I_{\max }}{I_{\operatorname{mix}}} & =\frac{\left(a_1+a_2ight)^2}{\left(a_1-a_2ight)^2} \ & =\frac{(3 k+2 k)^2}{(3 k-2 k)^2}=\frac{25}{1} \ I_{\operatorname{man}}: I_{\min } & =25: 1\end{aligned}$

Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum…

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