Light of wavelength $4000 Å$ is incident on a sodium surface for which the threshold wavelength of photo electrons is $5420 Å$. The work function of sodium is

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Aicharya · Accepted Answer

$\lambda = 4000 Å, \lambda_0=5420 Å$ $	herefore$ Work function, $\begin{aligned} \phi_0=\frac{12400}{\lambda_0(\mathrm{in} Å)} \mathrm{eV} & =\frac{12400}{5420} \ & =2.29 \mathrm{eV}\end{aligned}$

Light of wavelength $4000 Å$ is incident on a sodium surface for which the threshold wavelength of photo…

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