Light of wavelength ' $\lambda$ ' is incident on a single slit of width ' $a$ ' and distance between slit…
Light of wavelength ' $\lambda$ ' is incident on a single slit of width ' $a$ ' and distance between slit and screen is ' $D$ '. In diffraction pattern, if slit width is equal to the width of the central maximum then $\mathrm{D}=$
$\frac{\mathrm{a}^2}{\lambda}$
$\frac{\mathrm{a}}{\lambda}$
$\frac{a^2}{2 \lambda}$
$\frac{\mathrm{a}}{2 \lambda}$
Solution
Width of central maximum $=\frac{2 \lambda \mathrm{D}}{\mathrm{a}}=\mathrm{a}$
$\therefore \mathrm{D}=\frac{\mathrm{a}^2}{2 \lambda}$