Light of wavelength 300   nm in medium A enters into medium B through a plane surface. If the frequency…

Light of wavelength 300 nm in medium A enters into medium B through a plane surface. If the frequency of light is 5×1014 Hz and the ratio of speed in medium A to that is medium B is 45, the absolute refractive index of medium B is,
  1. 1.6
  2. 1.5
  3. 1.3
  4. 1.45

Solution

Absolute refractive index of medium A, μA=cνAλ=3×1085×1014×300×10-9=2

Refractive index is inversely proportional to the velocity of light.

⇒μBμA=vAvB=45

⇒μB=μA45=85

⇒μB=1.6

Asked in: AP EAMCET 2021 (19 Aug Shift 2)

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