Light green crystals of ferrous sulphate lose water molecules and turn brown on exposure to air. This is due…

Light green crystals of ferrous sulphate lose water molecules and turn brown on exposure to air. This is due to its oxidation to
  1. $\mathrm{Fe}_{2} \mathrm{O}_{3}$
  2. $\mathrm{Fe}_{2} \mathrm{O}_{3} \cdot \mathrm{H}_{2} \mathrm{O}$
  3. $\mathrm{Fe}(\mathrm{OH}) \mathrm{SO}_{4}$
  4. $\mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{FeO}$

Solution

$\mathrm{Fe}(\mathrm{OH}) \mathrm{SO}_{4}$
$\mathrm{FeSO}_{4} \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{Fe}(\mathrm{OH}) \mathrm{SO}_{4}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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