Light from a source travels out with a velocity \(c\). If the source moves away from the observer with a…
Light from a source travels out with a velocity \(c\). If the source moves away from the observer with a velocity \(v\), then the relative velocity of light with respect to observer is
\(\mathrm{C}\)
\(c+v\)
\(c-v\)
\(\sqrt{c^2+v^2}\)
Solution
The speed of light in vacuum is the same for any incrtial reference as \(c\left(3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)\). This is true no matter how fast a light source is moving relative to an observer.