Let z 1 , z 2 be the roots of the equation z 2 + a z + 12 = 0 and z 1 ,   z 2 form an equilateral…

Let z1,z2 be the roots of the equation z2+az+12=0 and z1, z2 form an equilateral triangle with origin. Then, the value of a is

Solution

z2+az+12=0

z1+z2=-a and z1z2=12

If 0, z1, z2 are vertices of equilateral triangles

z2=z1eiπ3

z2=z112+i32

2z2-z1=3iz1

squaring both sides

4z22+z12-4z1z2=-3z12

z1+z22=3z1z2

a2=3×12

a=6

Asked in: JEE Main 2021 (18 Mar Shift 1)

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