Let z = - 1 +   3 i 2 , where i =   - 1 , and r ,   s ∈ 1 ,   2 ,   3 . Let P…

Let z=-1+ 3i2 , where i= -1 , and r, s1, 2, 3. Let P=-zrz2sz2szr and I be the identity matrix of order 2. Then the total number of ordered pairs (r,s) for which P2=-I is

Solution

z=ω (ω is complex cube root of unity)
P=-ωrω2sω2sωrP2=-I
P2=ω2r+ω4sωr+2s-1r+1ωr+2s-1r+1ω4s+ω2r= -I = -100-1
-1r+1=0r is odd  r=1, 3
Also ω2r+ω4s= -1
r 3
By r=1ω2+ω4s=-1 ω4s=ω=ω4
s=1
r, s=1, 1
Only 1 pair

Asked in: JEE Advanced 2016 (Paper 1)

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