Let y = y x be the solution of the differential equation sin ⁡ x d y d x + y cos x ⁡ = 4 x ,…

Let y=yx be the solution of the differential equation sinxdydx+ycosx=4x, x0, π. If yπ2=0, then yπ6 is equal to
  1. -49π2
  2. 493π2
  3. -893π2
  4. -89π2

Solution

dydx+ycot x=4xsinx, x0, π

I.F. =ecotx=elnsinx=sinx

y sinx=4xsinx.sinx dx

ysinx=2x2+c

yπ2=0

0×1=2×π22+c

c=-π22

yπ6=2×π62-π2212=π218-π22×2

=π29-π2

=-8π29

Asked in: JEE Main 2018 (08 Apr)

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