Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6 , 11 , …   , and Y be the set consisting of the first 2018 terms of the arithmetic progression 9,16,23 , …   . Then, the number of elements in the set X ∪ Y is___.

Question

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6 , 11 , &#8230; &#160; , and Y be the set consisting of the first 2018 terms of the arithmetic progression 9,16,23 , &#8230; &#160; . Then, the number of elements in the set X &#8746; Y is___.

Aicharya · Accepted Answer

X : 1 , &#160; 6 , &#160; 11 , &#160; &#8230; , 10086 Y : 9 , &#160; 16 , &#160; 23 , &#8230; . , 14128 X &#8745; Y : 16 , &#160; 51 , &#160; 86 , &#8230; . . Let m = n X &#8745; Y &#8756; &#160; &#160; 16 + m - 1 &#215; 35 &#8804; 10086 &#8658; &#160; &#160; m &#8804; 288.71 &#8658; &#160; &#160; m = 288 &#8756; &#160; &#160; n X &#8746; Y = n X + n Y - n X &#8745; Y = &#160; &#160; 2018 + 2018 - 288 = 3748

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6 , 11 , …   …

Solution

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6 , 11 , &#8230; &#160; …

Solution

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1,6 , 11 , … …