Let X be a random variable such that the probability function of a distribution is given by P X = 0 = 1 2 ,…

Let X be a random variable such that the probability function of a distribution is given by PX=0=12,PX=j=13jj=1,2,3,,. Then the mean of the distribution and P(X is positive and even) respectively, are:
  1. 38 and 18
  2. 34 and 18
  3. 34 and 19
  4. 34 and 116

Solution

We have, PX=0=12,PX=j=13jj=1,2,3,,

Mean =ΣXiPi=r=0r·13r=34

P(X is even) =132+134+

=191-19

=1989=18.

Asked in: JEE Main 2021 (25 Jul Shift 2)

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