Let $A=\begin{bmatrix} x & y & z \\ y & z & x \\ z & x & y \end{bmatrix}$, where $x$, $y$ and $z$ are real…

Let $A=\begin{bmatrix} x & y & z \\ y & z & x \\ z & x & y \end{bmatrix}$, where $x$, $y$ and $z$ are real numbers such that $x+y+z > 0$ and $xyz = 2$. If $A^2 = I_3$, then the value of $x^3 + y^3 + z^3$ is

Solution

A2=I

AA'=I (as A'=A)

A is orthogonal

So, x2+y2+z2=1 and xy+yz+zx=0

x+y+z2=1+2×0

x+y+z=1

Thus, 

x3+y3+z3=3×2+1×1-0

= 7

Asked in: JEE Main 2021 (25 Feb Shift 1)

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