Let the vectors a → , b → , c → be such that | a → | = 2 , | b → | = 4 and | c…

Let the vectors a,b,c be such that |a|=2,|b|=4 and |c|=4. If the projection of b on a is equal to the projection of c on a and b is perpendicular to c, then the value of |a+b-c| is

Solution

b.a=c.a
a+b-c2=|a|2+|b|2+|c|2+2a·b-b·c-a·c
=4+16+16+2(a.b-0-a.b)=36
|a+b-c|=6

Asked in: JEE Main 2020 (05 Sep Shift 2)

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