Let the numbers 2 ,   b ,   c be in an A.P. and A = 1 1 1 2 b c 4 b 2 c 2 . If d e t ( A )  …

Let the numbers 2, b, c be in an A.P. and A=1112bc4b2c2 . If det(A) [2,16], then c lies in the interval:
  1. 2,3
  2. 4,6
  3. 3,2+234
  4.  2+234,4

Solution

1112bc4b2c2C2C2-C1, C3C3-C11002b-2c-24b2-4c2-4=b-2c-2c-b
Let common difference of AP=d
b=2+d,   c=2+2d
A=d×2d×d=2d32, 16
d31, 8d1, 22d2, 4
2+2d4, 6
c4, 6

Asked in: JEE Main 2019 (08 Apr Shift 2)

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