Let the function f : 0 , π → ℝ be defined by f θ = sin θ + cos θ 2 + sin…

Let the function f:0,π be defined by fθ=sinθ+cosθ2+sinθ-cosθ4. Suppose the function f has a local minimum at θ precisely when θλ1π,,λrπ, where 0<λ1<<λr<1. Then the value of  λ1++λr is_______

Solution

fθ=1+sin2θ+1-sin2θ2

=sin22θ-sin2θ+2

=sin2θ-122+74

It has minima when sin2θ=12=sinπ6

θ0,π

2θ=π6,5π6

θ=π12,5π12

λ1=112, λ2=512

sum=12.

Asked in: JEE Advanced 2020 (Paper 2)

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