Let the centroid of an equilateral triangle A B C be at the origin. Let one of the sides of the equilateral…

Let the centroid of an equilateral triangle ABC be at the origin. Let one of the sides of the equilateral triangle be along the straight line x+y=3. If R and r be the radius of circumcircle and incircle respectively of ΔABC, then (R+r) is equal to :
  1. 92
  2. 72
  3. 22
  4. 32

Solution

Distance from origin to line x+y=3 is inradius.

r=OM=32

& sin30°=12=rR⇒R=62

∴r+R=92

Asked in: JEE Main 2021 (18 Mar Shift 2)

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