Let P : y 2 = 4 a x ,   a > 0 be a parabola with focus S .Let the tangents to the parabola P make…

Let P:y2=4ax, a>0 be a parabola with focus S.Let the tangents to the parabola P make an angle of π4 with the line y=3x+5 touch the parabola P at A and B. Then the value of a for which A, B and S are collinear is:
  1. 8 only
  2. 2 only
  3. 14only
  4. any a>0

Solution

Lines making angle $\frac{\pi}{4}$ with $y=3x+5$ So using formula $\tan \alpha = \frac{m_2 - m_1}{1 + m_1 m_2}$, we have slope $-2 \& \frac{1}{2}$.

Which are perpendicular to each-other so, A, S, Bare collinear for all a>0. (by property that perpendicular tangents will lie on directrix and chord of contact will pass through focus, so the points are collinear )

   

Asked in: JEE Main 2022 (29 Jun Shift 2)

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