Let P x = x 2 + b x + c be a quadratic polynomial with real coefficients such that ∫ 0 1 P x d x = 1 and P x leaves remainder 5 when it is divided by x - 2 Then the value of 9 b + c is equal to:

Question

Let P x = x 2 + b x + c be a quadratic polynomial with real coefficients such that &#8747; 0 1 P x d x = 1 and P x leaves remainder 5 when it is divided by x - 2 Then the value of 9 b + c is equal to:

Aicharya · Accepted Answer

&#8747; 0 1 x 2 + b x + c d x = 1 1 3 + b 2 + c = 1 &#160;&#160; &#8658; &#160; b 2 + c = 2 3 3 b + 6 c = 4 &#160; . . . 1 P 2 = 5 4 + 2 b + c = 5 2 b + c = 1 &#160; . . . 2 From 1 &#160; &#38; &#160; 2 b = 2 9 &#160; &#38; &#160; c = 5 9 9 b + c = 7

Let P x = x 2 + b x + c be a quadratic polynomial with real coefficients such that ∫ 0 1 P x d x = 1…

Solution

Let P x = x 2 + b x + c be a quadratic polynomial with real coefficients such that &#8747; 0 1 P x d x = 1…

Solution

Let P x = x 2 + b x + c be a quadratic polynomial with real coefficients such that ∫ 0 1 P x d x = 1…