Let P = θ : sin θ - cos θ = 2 cos θ and Q = θ : sin θ + cos θ = 2 sin…

Let P=θ:sinθ-cosθ=2cosθ and Q=θ:sinθ+cosθ=2sinθ, be two sets. Then
  1. PQ and Q-P  ϕ
  2. QP
  3. P=Q
  4. PQ

Solution

P: sinθ-cosθ= 2cosθ

sinθ=cosθ+ 2cosθ

tanθ= 2+1

Q:sinθ+cosθ= 2sinθ2-1sinθ=cosθ  

=tanθ= 12-1= 2+1

Asked in: JEE Main 2016 (10 Apr Online)

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