Let P S be the median of the triangle with vertices P ( 2 , 2 ) ,   Q ( 6 , - 1 ) and R ( 7 , 3 ) . The…

Let PS be the median of the triangle with vertices P(2,2), Q(6,-1) and R(7,3). The equation of the line passing through (1,-1) and parallel to PS is 
  1. 4x+7y+3=0
  2. 2x-9y-11=0
  3. 4x-7y-11=0
  4. 2x+9y+7=0

Solution

P(2,2); Q(6,-1); R(7,3)

S is the midpoint of Q and R.

∴   S132, 1

∴ Slope of PS=2-12-132=1-92=-29

Therefore, the equation of the line passing through (1,-1) and parallel to PS is

 y+1=-29x-1

 9y+9=-2x+2

 2x+9y+7=0

Asked in: JEE Main 2014 (06 Apr)

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