Let PQ be a chord of the parabola $y^2=12 x$ and the midpoint of PQ be at $(4,1)$. Then, which of the…
- $(3,-3)$
- $(2,-9)$
- $\left(\frac{3}{2},-16\right)$
- $\left(\frac{1}{2},-20\right)$
Solution

$\begin{aligned} & T=S_1 \\ & y-6(x+4) \\ & =1-48 \\ & 6 x-y=23 \end{aligned}$
Option $4\left(\frac{1}{2},-20\right)$ will satisfy
Asked in: JEE Main 2024 (04 Apr Shift 2)