Let P be a point on the ellipse x 2 9 + y 2 4 = 1 . Let the line passing through P and parallel to y - axis…

Let P be a point on the ellipse x29+y24=1. Let the line passing through P and parallel to y-axis meet the circle x2+y2=9 at point Q such that P and Q are on the same side of the x-axis. Then, the eccentricity of the locus of the point R on PQ such that PR:RQ=4:3 as P moves on the ellipse, is:
  1. 1119
  2. 1321
  3. 13923
  4. 137

Solution

Given equation of ellipse and circle are x29+y24=1 and x2+y2=9.

P3cosθ, 2sinθ and Q3cosθ, 3sinθ

Let, Rh,k

h=3cosθ, k=187sinθ

h3=cosθ, 7k18=sinθ

So, locus of R is given by, x29+49y2324=1.

e=132449×9

e=11721

e=137

Asked in: JEE Main 2024 (01 Feb Shift 2)

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