Let m , n ∈ N and gcd 2 ,   n = 1 . If 30 30 0 + 29 30 1 + … . . + 2 30 28 + 1 30 29 = n .…

Let m,nN and gcd2, n=1. If 30300+29301+..+23028+13029=n.2m, then n+m is equal to _______. (Here nk=Ckn)

Solution

30C030+29C130++2C2830+1C2930

=30C3030+29C2930++2C230+1C130

=r=130rCr30

=r=130r30rCr-129

=30r=130Cr-129

=30C029+C129+C229++C2929

=30229=15230=n2m

 n=15,m=30

n+m=45

Asked in: JEE Main 2021 (26 Feb Shift 1)

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