Let $A=\{0,1,2,3,4,5\}$. Let $R$ be a relation on A defined by $(x, y) \in R$ if and only if max $\{x, y\}…
- both are true
- both are false
- only $\left(\mathrm{S}_2\right)$ is true
- only $\left(\mathrm{S}_1\right)$ is true
Solution
$\mathrm{R} \equiv\{(0,3),(3,0),(0,4),(4,0),(1,3),(3,1),(1,4)$,
$(4,1),(2,3),(3,2),(2,4),(4,2),(3,3),(3,4),(4,3)$,
$(4,4)\}$
Total 16 elements
Not reflexive as $(0,0), \ldots \ldots,(2,2) \notin \mathrm{R}$
Symmetric $\because \forall$ all a,b
$(a, b) \&(b, a) \in R$
Not transitive $\because(0,3),(3,1) \in R$
but $(0,1) \notin \mathrm{R}$
$\Rightarrow$ Only $\mathrm{S}_2$ correct ^
Asked in: JEE Main 2025 (08 Apr Shift 2)