Let $\alpha \in \mathbb{R}$. If the line $(\alpha+1) x+\alpha y+\alpha=1$ passes through a fixed point $(h,…
Let $\alpha \in \mathbb{R}$. If the line $(\alpha+1) x+\alpha y+\alpha=1$ passes through a fixed point $(h, k)$ for all $\alpha$, then $h^2+k^2=$
- 2
- 5
- 4
- $\frac{1}{4}$
Solution
$\begin{aligned} & \text { }(\alpha+1) x+\alpha y+\alpha-1=0 \\ & \alpha(x+y+1)+x-1=0 ; h=1,1+k+1=0 \Rightarrow k=-2 \\ & h^2+k^2=5\end{aligned}$
Asked in: AP EAMCET 2024 (21 May Shift 1)
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