Let $\alpha \in \mathbb{R}$. If the line $(\alpha+1) x+\alpha y+\alpha=1$ passes through a fixed point $(h,…

Let $\alpha \in \mathbb{R}$. If the line $(\alpha+1) x+\alpha y+\alpha=1$ passes through a fixed point $(h, k)$ for all $\alpha$, then $h^2+k^2=$
  1. 2
  2. 5
  3. 4
  4. $\frac{1}{4}$

Solution

$\begin{aligned} & \text { }(\alpha+1) x+\alpha y+\alpha-1=0 \\ & \alpha(x+y+1)+x-1=0 ; h=1,1+k+1=0 \Rightarrow k=-2 \\ & h^2+k^2=5\end{aligned}$

Asked in: AP EAMCET 2024 (21 May Shift 1)

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