Let H : x 2 a 2   - y 2 b 2 = 1 , where a > b > 0 , be a hyperbola in the xy-plane whose…

Let H:x2a2 -y2b2=1 , where a>b>0, be a hyperbola in the xy-plane whose conjugate axis LM subtends an angle of 60o at one of its vertices N. Let the area of the triangle LMN be 43.

LIST-I LIST-II
A. The length of the conjugate axis of H is P. 8
B. The eccentricity of H is Q. 43
C. The distance between the foci of H is R. 23
D. The length of the latus rectum of H is S. 4
The correct option is:
  1. a-r;b-q;c-s;d-p;
  2. a-q;b-r;c-s;d-p;
  3. a-r;b-s;c-p;d-q;
  4. a-s;b-r;c-p;d-q;

Solution


tan30o=ba
a=b3
Now area of LMN=12.2b.b3
43=3b2
b=2 & a=23
e=1+b2a2=23
P. Length of conjugate axis =2b=4
So P4
Q. Eccentricity e=23
So Q3
R. Distance between foci =2ae
=22323=8
So, R1
S. Length of latus rectum =2b2a=22223=43
So S2

Asked in: JEE Advanced 2018 (Paper 2)

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