Let f x be a differentiable function defined on 0 ,   2 such that f ' x = f ' 2 - x for all x…

Let fx be a differentiable function defined on 0, 2 such that f'x=f'2-x for all x0,2,f0=1 and f2=e2. Then the value of 02fxdx is
  1. 21+e2
  2. 1+e2
  3. 1-e2
  4. 21-e2

Solution

f'x=f'2-x

fx=-f2-x+c

put x=0

f0=-f2+c

c=f0+f2=1+e2

so, fx+f2-x=1+e2

I=02fxdx

I=02f2-xdx

2I=02fx+f2-xdx

2I=1+e202dx

I=1+e2

Asked in: JEE Main 2021 (24 Feb Shift 2)

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