Let f : R → R be a function such that f 2 - x = f 2 + x and f 4 - x = f 4 + x , for all x ∈ R…

Let f:RR be a function such that f2-x=f2+x and f4-x=f4+x, for all xR and 02fxdx=5. Then the value of 1050fxdx is
  1. 100
  2. 125
  3. 80
  4. 200

Solution

f2-x=f2+x and f4-x=f(4+x)

Then curve is symmetric about x=2 and x=4

    The curve is periodic with period 4

Given 02fxdx=5

04fxdx=202fxdx=10

1050fxdx=24+2124+2fxdx

=12-204fxdx

=10×10=100

Asked in: JEE Main 2015 (11 Apr Online)

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