Let electronegativity, ionisation energy and electron affinity be represented as EN, IP and EA respectively.…

Let electronegativity, ionisation energy and electron affinity be represented as EN, IP and EA respectively. Which one of the following equation is correct according to Mulliken?
  1. $\mathrm{EN}=\mathrm{IP} \times \mathrm{EA}$
  2. $\mathrm{EN}=\frac{\mathrm{IP}}{\mathrm{EA}}$
  3. $\mathrm{EN}=\frac{\mathrm{IP}+\mathrm{EA}}{2}$
  4. $\mathrm{EN}=\mathrm{IP}-\mathrm{EA}$

Solution

Mulliken suggested that EN of an element is the average of its IP and EA.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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