Let E 1 and E 2 be two events such that the conditional probabilities P E 1 ∣ E 2 = 1 2 , P E 2 &#8739…

Let E1 and E2 be two events such that the conditional probabilities PE1E2=12, PE2E1=34 and PE1E2=18. Then
  1. PE1E2=PE1·PE2
  2. PE1'E2'=PE1'·PE2
  3. PE1E2'=PE1·PE2
  4. PE1E2=PE1PE2

Solution

PE1E2PE2=12, PE2E1PE1=34, PE1E2=18

 PE2=14, PE1=16, PE1E2=16+14-18=724

PE'E2'=PE1E2'=1-724=1724

PE2'=34  PE1E2=PE1PE2'

PE1E2'=PE1-PE1E2=16-18=124

PE1E2'=PE1·PE2

Asked in: JEE Main 2022 (25 Jun Shift 1)

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