Let E ,   F and G be three events having probabilities P ( E ) = 1 8 , P ( F ) = 1 6 and P ( G ) = 1 4 …

Let E, F and G be three events having probabilities P(E)=18,P(F)=16 and P(G)=14, and let P(EFG)=110
For any event H, if Hc denotes its complement, then which of the following statements is (are) TRUE ?
  1. PEFGc140
  2. PEcFG115
  3. P(EFG)1324
  4. PEcFcGc512

Solution

(i)PEFGc=PEF-PEFGPE-110=18-110=140 (ii)PEcFG=P(FG)-P(EFG)P(F)-110=16-110=115 (iii) PEFGPE+PF+PG=18+16+14=3+4+624=1324 (iv)PEcFcGcmax=1-P(EFG)min P(EFG)min=14 ThusPEcFcGc34

Asked in: JEE Advanced 2021 (Paper 1)

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