Let $\bar{u}, \bar{v}, \bar{w}$ be vectors such that $|\bar{u}|=1,|\bar{v}|=2,|\bar{w}|=3$. If the…

Let $\bar{u}, \bar{v}, \bar{w}$ be vectors such that $|\bar{u}|=1,|\bar{v}|=2,|\bar{w}|=3$. If the projection of $\bar{v}$ on $\bar{u}$ is equal to that of $\bar{w}$ on $\bar{u}$, and the vectors $\bar{v}, \bar{w}$ are perpendicular to each other, then $|\bar{u}-\bar{v}+\bar{w}|=$
  1. $2$
  2. $\sqrt{7}$
  3. $\sqrt{14}$
  4. $14$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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