Let α , β be two roots of the equation x 2 + 20 1 / 4 x + 5 1 / 2 = 0 . Then α 8 + β 8…

Let α,β be two roots of the equation x2+201/4x+51/2=0. Then α8+β8 is equal to
  1. 10
  2. 100
  3. 50
  4. 160

Solution

Given, 

x2+201/4x+51/2=0

x2+5=-x2014

x2+52=20x2

x4+5+2×x2×5=20x2

x4=-5x8=25

So, α8+β8=25+25=50

Asked in: JEE Main 2021 (27 Jul Shift 1)

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