Let $\bar{a}, \bar{b}, \bar{c}$ be three vectors such that $|\bar{a}|=|\bar{c}|=1,|\bar{b}|=4,|\bar{b}…

Let $\bar{a}, \bar{b}, \bar{c}$ be three vectors such that $|\bar{a}|=|\bar{c}|=1,|\bar{b}|=4,|\bar{b} \times \bar{c}|=\sqrt{15}$. If $\lambda \bar{a}=\bar{b}-2 \bar{c}$, then the value of $\lambda$ is
  1. $\pm 1$
  2. $\pm 2$
  3. $\pm 3$
  4. $\pm 4$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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