Let $p, q, r$ be three statements such that the truth value of $(p \wedge q) \rightarrow(\sim q \vee r)$ is $F$. Then the truth values of $p, q, r$ are respectively

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Aicharya · Accepted Answer

From the above truth table, $(p \wedge q) \rightarrow(\sim q \vee r)$ is false if, truth value of $p, q$, r are $\mathrm{T}, \mathrm{T}, \mathrm{F}$

Let $p, q, r$ be three statements such that the truth value of $(p \wedge q) \rightarrow(\sim q \vee r)$ is…

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