Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the…

Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region EI , EII and EIII

 

  1. E→I=2σ∈0n^,E→II=0,E→III=2σ∈0n^
  2. E→I=0,E→II=σ∈0n^,E→III=0
  3. E→I=σ2∈0n^,E→II=0,E→III=σ2∈0n^
  4. E→I=-σ∈0n^,E→II=0,E→III=σ∈0n^

Solution

Electric field due to charged sheet for charge density +σ is E→=+σ2∈0 and for -σ is E→=-σ2∈0.

Assuming RHS to be n^

E→I=σ2∈0-n^+σ2∈0-n^=-σ∈0n^  (leftwards)

E→II=σ2∈0-n^+σ2∈0n^=0

E→III=σ2∈0n^+σ2∈0n^=σ∈0n^    (rightwards)

Asked in: JEE Main 2023 (01 Feb Shift 1)

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